(X-1)(x+3)=x^2+5x-7

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Solution for (X-1)(x+3)=x^2+5x-7 equation: 



(X-1)(X+3)=X^2+5X-7

We move all terms to the left:

(X-1)(X+3)-(X^2+5X-7)=0

We get rid of parentheses

-X^2+(X-1)(X+3)-5X+7=0

We multiply parentheses ..

-X^2+(+X^2+3X-1X-3)-5X+7=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+3X-1X-3)-5X+7=0

We get rid of parentheses

-1X^2+X^2+3X-1X-5X-3+7=0

We add all the numbers together, and all the variables

-3X+4=0

We move all terms containing X to the left, all other terms to the right

-3X=-4

X=-4/-3

X=1+1/3

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